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In the casino industry, a confidence level of either 90% and 95% is the typically used. I
chose to use the more conservative 95% confidence level.
My calculations can be illustrated in more detail by focusing on the Chart and reviewing
1999 using the “average” assumptions.
The reported wins, $131,281, was indicated from the W2-Gs. The total number of
games, 437,500, is the product of bets/hour x hours/day x days of gambling in 1999, or
250 x 7 x 250. The total money wagered, $3,937,500, is the product of the number of
games x the average bet size of $9. As I already knew the winning from top awards, I therefore
had to calculate the expected base-game awards (all awards excluding those which would trigger
a W2-G filing) based on a base-game RTP of 80.5%. = 83.0% - 2.5% for top awards. The
product, $3,937,500 of total wagers x 80.5%, is the expected base-game awards $3,169,688.
Adding the $131,281 of known top awards with the $3,169,688 of expected base-game awards
yielded a total expected awards of $$3,300,969. The expected total win was therefore -
$3,937,500 + $3,300,969 = -$636,532, or in other words, a loss of $636K
Because of the stochastic nature of gambling, Mr. Gagliardi’s actual winnings were likely
to have varied somewhat from the expected average due to the effect of natural random
fluctuations. To determine the expected range due to these possible fluctuations, I relied
industry-standard confidence intervals. The plus/minus variation range about an expected value
can be expressed as:
normal variation range = (z σ /√n)
where:
z = normal distribution z-score. For a 95% confidence level, we use z=1.960
σ = standard deviation of the base game, or 5.6